Question

mrs. hogan is teaching a 5th grade class. she is standing 5 meters in front of chandler. austen is sitting to chandler’s right. if austen and mrs. hogan are 13 meters apart, how far apart are chandler and austen?
meters

Explanation:

Step1: Identify the triangle type

This forms a right triangle where Mrs. Hogan to Chandler is one leg (\(a = 5\) m), Chandler to Austen is another leg (\(b\)), and Mrs. Hogan to Austen is the hypotenuse (\(c = 13\) m). Use the Pythagorean theorem: \(a^2 + b^2 = c^2\).

Step2: Solve for \(b\)

Substitute values: \(5^2 + b^2 = 13^2\) → \(25 + b^2 = 169\). Subtract 25: \(b^2 = 169 - 25 = 144\). Take square root: \(b = \sqrt{144} = 12\).

Answer:

12