QUESTION IMAGE
Question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer.
a flashlight is projecting a triangle onto a wall, as shown below.
image of two similar triangles with a flashlight, original triangle has sides 15, 15, 20; projection has sides 30, 30, n
the original triangle and its projection are similar. what is the missing length n on the projection?
options: ( 22\frac{1}{2} ), 10, 35, 40
Step1: Identify similar triangles ratio
The triangles are similar, so corresponding sides are proportional. The ratio of sides: \( \frac{30}{15} = 2 \).
Step2: Apply ratio to find \( n \)
The side of length 20 in the original corresponds to \( n \) in the projection. Multiply 20 by the ratio: \( n = 20 \times 2 = 40 \)? Wait, no, wait. Wait, the original triangle has sides 15, 15, 20. The projection has 30, 30, \( n \). Wait, the ratio of 30 to 15 is 2, so the ratio of similarity is 2. So the side corresponding to 20 (original) should be \( 20 \times 2 = 40 \)? Wait, but let's check again. Wait, maybe I mixed up. Wait, the original triangle: sides 15, 15, 20. The projection: 30, 30, \( n \). So the ratio of projection to original is \( \frac{30}{15} = 2 \). So \( n = 20 \times 2 = 40 \). Wait, but let's confirm. Wait, similar triangles: corresponding sides are proportional. So \( \frac{30}{15} = \frac{n}{20} \). Solve for \( n \): \( n = \frac{30 \times 20}{15} = \frac{600}{15} = 40 \). Yes, that's correct.
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40 (corresponding to the option "40")