Question

\dont move my bookcase!\ says johannas cat. johanna wants to move that bookcase which weigh 51.2 kg across a smooth floor using a net force of 67 n. what would be the approximate (round, about) acceleration of the bookshelf? a 1.3 m/s² b 17.8 c 118.2 m/s² d 1.3

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(a\), so the formula becomes \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 67\space N\) and \(m=51.2\space kg\). Then \(a=\frac{67}{51.2}\).

Step3: Calculate the value of \(a\)

\(a=\frac{67}{51.2}\approx1.3\space m/s^{2}\) (since options A and D have the value \(1.3\), but acceleration has unit \(m/s^{2}\))

Answer:

A. \(1.3\space m/s^{2}\)