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3. a mom monster has homozygous recessive alleles for no horns (h). cro…

Question

  1. a mom monster has homozygous recessive alleles for no horns (h). cross her alleles with a dad monster who has homozygous dominant alleles.

a. what percentage of dragons have horns?
b. what genotypes appear from this cross?

Explanation:

Step1: Determine the parents' genotypes

The mom monster has homozygous recessive alleles, so her genotype is \( hh \). The dad monster has homozygous dominant alleles, so his genotype is \( HH \).

Step2: Create the Punnett square

When crossing \( hh \) (mom) with \( HH \) (dad), all the offspring will have the genotype \( Hh \).

$$\begin{array}{|c|c|} \hline H & H \\ \hline h & Hh \\ \hline h & Hh \\ \hline \end{array}$$

Step3: Analyze the phenotype (A)

Since \( H \) (horns) is dominant over \( h \) (no horns), all offspring (\( Hh \)) will have horns. So the percentage of dragons with horns is \( 100\%\).

Step4: List the genotypes (B)

From the Punnett square, the only genotype that appears is \( Hh \).

Answer:

A. \( 100\%\) of dragons have horns.
B. The genotype that appears from this cross is \( Hh \).