Question

s 6 miles north and then 10 miles south. his displacement is 4 miles south 4 miles north

Explanation:

Step1: Define directions as vectors

Let north be the positive - direction and south be the negative - direction. The first displacement $d_1 = 6$ miles (north) and the second displacement $d_2=- 10$ miles (south).

Step2: Calculate the net displacement

The net displacement $D=d_1 + d_2$. Substitute the values: $D = 6+( - 10)=6 - 10=-4$ miles.

Answer:

4 miles south