QUESTION IMAGE
Question
solve for x.
Step1: Identify Midsegment Theorem
In a triangle, the midsegment (a segment connecting midpoints of two sides) is parallel to the third side and half its length. Here, \( U \) is midpoint of \( GH \) (since \( GU = UH \)) and \( T \) is midpoint of \( GF \) (since \( GT = TF \)), so \( UT \) is midsegment. Thus, \( UT=\frac{1}{2}FH \).
Step2: Set Up Equation
Given \( UT = x + 15 \) and \( FH = x + 21 \), substitute into midsegment formula:
\( x + 15=\frac{1}{2}(x + 21) \)
Step3: Solve for \( x \)
Multiply both sides by 2: \( 2(x + 15)=x + 21 \)
Expand left side: \( 2x + 30=x + 21 \)
Subtract \( x \) from both sides: \( 2x - x+ 30=x - x+ 21 \)
Simplify: \( x + 30=21 \)
Subtract 30 from both sides: \( x + 30 - 30=21 - 30 \)
Simplify: \( x=-9 \)
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\( x = -9 \)