Question

simplify.
$(y^{x} cdot y^{-x})^{4}$

Explanation:

Step1: Use exponent rule \(a^m \cdot a^n = a^{m + n}\)

Inside the parentheses, \(y^x \cdot y^{-x}=y^{x+(-x)} = y^{0}\)

Step2: Simplify \(y^0\) and apply power rule \((a^m)^n=a^{m\cdot n}\)

We know that \(y^0 = 1\) (for \(y
eq0\)), then \((y^{0})^{4}=y^{0\times4}=y^{0} = 1\)

Answer:

\(1\)