Question

simplify.
\\(\frac{4y^2 - 32y}{3y^2 - 24y}\\)

Explanation:

Step1: Factor numerator and denominator

Factor out the greatest common factor from the numerator \(4y^{2}-32y\): \(4y(y - 8)\)
Factor out the greatest common factor from the denominator \(3y^{2}-24y\): \(3y(y - 8)\)
So the fraction becomes \(\frac{4y(y - 8)}{3y(y - 8)}\)

Step2: Cancel common factors

Cancel out the common factors \(y\) (assuming \(y
eq0\)) and \((y - 8)\) (assuming \(y
eq8\)) from the numerator and the denominator.
After canceling, we are left with \(\frac{4}{3}\)

Answer:

\(\frac{4}{3}\)