Question

\\(\frac{2^3(4^2 - 4)}{2 \times 3}\\)

Explanation:

Step1: Calculate exponents and parentheses

First, calculate the exponents and the operation inside the parentheses. For \(2^3\), we have \(2^3 = 8\). For the parentheses \(4^2 - 4\), calculate \(4^2 = 16\), then \(16 - 4 = 12\). So now the expression becomes \(\frac{8\times12}{2\times3}\).

Step2: Calculate numerator and denominator

Calculate the numerator: \(8\times12 = 96\). Calculate the denominator: \(2\times3 = 6\). Now the expression is \(\frac{96}{6}\).

Step3: Divide the numerator by the denominator

Divide \(96\) by \(6\): \(\frac{96}{6}=16\).

Answer:

16