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. $\frac{11}{4} > x + \frac{9}{4}$

Question

. $\frac{11}{4} > x + \frac{9}{4}$

Explanation:

Step1: Subtract 9/4 from both sides

To isolate the term with \( x \), we subtract \( \frac{9}{4} \) from both sides of the inequality \( \frac{11}{4} > x + \frac{9}{4} \). This gives us \( \frac{11}{4} - \frac{9}{4} > x \).

Step2: Simplify the left - hand side

Simplify \( \frac{11}{4}-\frac{9}{4} \). Since the denominators are the same, we subtract the numerators: \( \frac{11 - 9}{4}=\frac{2}{4}=\frac{1}{2} \). So the inequality becomes \( \frac{1}{2}>x \), or \( x < \frac{1}{2} \).

Answer:

\( x < \frac{1}{2} \)