Question

find \\((0.6)a\\) for \\(a = \

$$\begin{bmatrix} -1 & 2 & 6 \\\\ 1 & 4 & 9 \\\\ 1 & 2 & 3 \\\\ -5 & 10 & -15 \\end{bmatrix}$$

\\).

\\(\circ\\) \\(\

$$\begin{bmatrix} -0.6 & 1.2 & 3.6 \\\\ 0.6 & 2.4 & 5.4 \\\\ 0.6 & 1.2 & 1.8 \\\\ -3 & 6 & -9 \\end{bmatrix}$$

\\)

\\(\circ\\) \\(\

$$\begin{bmatrix} -6 & 12 & 36 \\\\ 0.6 & 24 & 5.4 \\\\ 0.6 & 1.2 & 1.8 \\\\ -3 & 6 & -90 \\end{bmatrix}$$

\\)

Explanation:

Identify the given matrix and scalar

Using the Scalar Multiplication knowledge point

$$ A =
LATEXBLOCK0
, \quad k = 0.6 $$

Multiply each element by the scalar

Using the Scalar Multiplication knowledge point

$$ (0.6)A =
LATEXBLOCK1
$$

Simplify the resulting matrix elements

Using the Scalar Multiplication knowledge point

$$ (0.6)A =
LATEXBLOCK2
$$

Answer:

• **(A) \(

$$\begin{bmatrix} -0.6 & 1.2 & 3.6 \\ 0.6 & 2.4 & 5.4 \\ 0.6 & 1.2 & 1.8 \\ -3 & 6 & -9 \end{bmatrix}$$

\) (Correct answer)**

• (B) \(

$$\begin{bmatrix} -6 & 12 & 36 \\ 0.6 & 24 & 5.4 \\ 0.6 & 1.2 & 1.8 \\ -3 & 6 & -90 \end{bmatrix}$$

\)