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factor. $2x^2 + 21x + 10$

Question

factor.
$2x^2 + 21x + 10$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to \(2\times10 = 20\) and add up to \(21\). The numbers are \(20\) and \(1\) since \(20\times1 = 20\) and \(20 + 1=21\).

Step2: Rewrite the middle term

Rewrite \(21x\) as \(20x+x\) in the quadratic expression: \(2x^{2}+20x + x+10\).

Step3: Group the terms

Group the first two terms and the last two terms: \((2x^{2}+20x)+(x + 10)\).

Step4: Factor out the GCF from each group

Factor out \(2x\) from the first group and \(1\) from the second group: \(2x(x + 10)+1(x + 10)\).

Step5: Factor out the common binomial factor

Factor out \((x + 10)\) from both terms: \((2x + 1)(x + 10)\).

Answer:

\((2x + 1)(x + 10)\)