Question

1. $2m^{4}n^{-3} cdot 2m^{4}n^{2}$

Explanation:

Step1: Multiply the coefficients

$2 \times 2 = 4$

Step2: Combine $m$ terms (add exponents)

$m^4 \cdot m^4 = m^{4+4} = m^8$

Step3: Combine $n$ terms (add exponents)

$n^{-3} \cdot n^2 = n^{-3+2} = n^{-1} = \frac{1}{n}$

Step4: Multiply all results together

$4 \cdot m^8 \cdot \frac{1}{n}$

Answer:

$\frac{4m^8}{n}$