Question

1. \\(\frac{58}{6}=\\) 7) \\(\frac{22}{6}=\\) 8) \\(\frac{3}{2}\\)

Explanation:

Step1: Simplify $\frac{58}{6}$

Divide 58 by 6: $58\div6 = 9$ with a remainder of 4. So $\frac{58}{6}=\frac{9\times6 + 4}{6}=9\frac{4}{6}=9\frac{2}{3}$ (or as an improper fraction simplified, $\frac{29}{3}$).

Step2: Simplify $-\frac{22}{6}$

Divide 22 by 6: $22\div6 = 3$ with a remainder of 4. So $-\frac{22}{6}=-\frac{3\times6 + 4}{6}=-3\frac{4}{6}=-3\frac{2}{3}$ (or as an improper fraction simplified, $-\frac{11}{3}$).

Step3: Simplify $\frac{3}{2}$

Divide 3 by 2: $3\div2 = 1$ with a remainder of 1. So $\frac{3}{2}=1\frac{1}{2}$ (or as a decimal, 1.5).

Answer:

1. $\boldsymbol{9\frac{2}{3}}$ (or $\boldsymbol{\frac{29}{3}}$)
2. $\boldsymbol{-3\frac{2}{3}}$ (or $\boldsymbol{-\frac{11}{3}}$)
3. $\boldsymbol{1\frac{1}{2}}$ (or $\boldsymbol{1.5}$)