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$4^{x + 2} = 256$

Question

$4^{x + 2} = 256$

Explanation:

Step1: Express 256 as a power of 4

We know that \(4^4 = 256\), so the equation \(4^{x + 2}=256\) can be rewritten as \(4^{x + 2}=4^4\).

Step2: Set exponents equal (since bases are same)

If \(a^m=a^n\) (where \(a>0,a
eq1\)), then \(m = n\). Here, \(a = 4\), \(m=x + 2\), and \(n = 4\). So we have the equation \(x+2=4\).

Step3: Solve for x

Subtract 2 from both sides of the equation \(x + 2=4\). We get \(x=4 - 2\), which simplifies to \(x = 2\).

Answer:

\(x = 2\)