Question

4 linear \\( a \

$$\begin{cases} y = 4 \\\\ x = -5y + 6 \\end{cases}$$

\\)

Explanation:

Step1: Substitute \( y = 4 \) into \( x=-5y + 6 \)

We know \( y = 4 \), so replace \( y \) in the second equation with 4. The equation becomes \( x=-5\times4 + 6 \).

Step2: Calculate the value of \( x \)

First, calculate \( -5\times4=-20 \), then \( x=-20 + 6=-14 \). So the solution of the system is \( x=-14 \), \( y = 4 \).

Answer:

The solution of the system \(

$$\begin{cases}y = 4\\x=-5y + 6\end{cases}$$

\) is \( x=-14 \), \( y = 4 \) (or written as the ordered pair \((-14,4)\)).