Question

1. \\(\frac{7}{4} \cdot \frac{13}{7}\\)

Explanation:

Step1: Simplify fractions

Notice that the 7 in the numerator of the first fraction and the 7 in the denominator of the second fraction can be canceled out. So we have $\frac{7}{4} \cdot \frac{13}{7} = \frac{1}{4} \cdot 13$ (because $\frac{7}{7}=1$).

Step2: Multiply the remaining numbers

Now we multiply 13 by $\frac{1}{4}$. $13\times\frac{1}{4}=\frac{13}{4}$ (or as a mixed number, $3\frac{1}{4}$, but usually improper fraction is fine here). Wait, actually, when we cancel the 7s, it's $\frac{7\times13}{4\times7}=\frac{13}{4}$ directly by canceling the common factor 7 in numerator and denominator.

Answer:

$\frac{13}{4}$ (or $3\frac{1}{4}$)