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Question
- mathematical representations predict the gravitational force between two 15-kg balls whose centers are 35 cm apart. what fraction is this of the weight of one ball?
- gravity if earth began to shrink, but its mass remained the same, what would happen to the value of g on earth’s surface?
- the value of g cavendish did his investigation using lead spheres. would his value of g be the same or different if he used copper spheres of equal mass? explain.
- laws or theories? kepler’s three statements and newton’s equation for gravitational attraction are called laws. were they ever theories? will they ever become theories?
- critical thinking picking up a rock requires less effort on the moon than on earth. how will the moons gravitational force affect the path of the rock if it is thrown horizontally?
Question 9
Step1: Recall Gravitational Force Formula
The gravitational force between two objects is given by Newton's law of universal gravitation: \( F = G\frac{m_1m_2}{r^2} \), where \( G = 6.67\times 10^{-11}\, \text{N}\cdot\text{m}^2/\text{kg}^2 \), \( m_1 \) and \( m_2 \) are the masses of the two objects, and \( r \) is the distance between their centers. The weight of an object is \( W = mg \), where \( g = 9.8\, \text{m/s}^2 \).
Step2: Convert Units
The mass of each ball \( m_1 = m_2 = 15\, \text{kg} \). The distance \( r = 35\, \text{cm} = 0.35\, \text{m} \).
Step3: Calculate Gravitational Force
Substitute the values into the gravitational force formula:
Step4: Calculate Weight of One Ball
The weight of one ball \( W = mg = 15\times 9.8 = 147\, \text{N} \).
Step5: Find the Fraction
The fraction is \( \frac{F}{W} = \frac{1.225\times 10^{-7}}{147} \approx 8.33\times 10^{-10} \).
The acceleration due to gravity on the surface of a planet is given by \( g = \frac{GM}{r^2} \), where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( r \) is the radius of the planet. If Earth shrinks (decreases \( r \)) but its mass \( M \) remains the same, from the formula, since \( g \) is inversely proportional to \( r^2 \), as \( r \) decreases, \( g \) will increase.
The gravitational constant \( G \) is a universal constant, meaning it does not depend on the material of the objects used in the experiment. Cavendish’s experiment to determine \( G \) relies on the gravitational force between two masses, which depends on the product of their masses, the distance between them, and \( G \). Since \( G \) is universal, using copper spheres of equal mass (same \( m_1 \), \( m_2 \), and \( r \)) would give the same value of \( G \) because \( G \) is independent of the material of the spheres.
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The gravitational force is approximately \( 1.23\times 10^{-7}\, \text{N} \), and the fraction of this force to the weight of one ball is approximately \( 8.33\times 10^{-10} \).