Question

mass: 3.00 g
molar mass
percent compositions
h₂o 18.015 11.18 h 88.81 o
so₂ 64.058 50.04 s 49.95 o
ru(co)₅ 241.12 41.91 ru 24.90 c 33.17 o
sf₆ 146.05 13.64 c 86.35 f
cf₄ 88.004 21.95 s 78.04 f
xef₄ 207.29 63.34 xe 36.35 f
mass (g)
amount (mol)
particles
h₂o 3.00 0.167 1.00 × 10²³
h 0.335 0.333 2.01 × 10²³
o 2.66 0.167 1.00 × 10²³
now examine the compound cf₄. set the mass to 6.0 g.
what is the ratio
\\( \frac { \text { number } f \text { atoms } } { \text { number } c \text { atoms } } \\) ?
enter your answer as an integer.
6.327

Explanation:

Step1: Analyze the chemical formula of \(CF_4\)

The chemical formula \(CF_4\) indicates that for every 1 carbon (\(C\)) atom, there are 4 fluorine (\(F\)) atoms.

Step2: Determine the ratio

The ratio of the number of \(F\) atoms to the number of \(C\) atoms is based on the sub - scripts in the chemical formula.

Answer:

4