Question

if ( mangle rxu = 128^{circ} ), then what is ( mangle txs )?

Explanation:

Step1: Use the linear - pair relationship

Angles \( \angle RXU\) and \( \angle TXS\) form a linear pair. The sum of angles in a linear pair is \(180^{\circ}\).
Let \(m\angle TXS=x\). Then \(m\angle RXU + x=180^{\circ}\).

Step2: Solve for \(x\)

Given \(m\angle RXU = 128^{\circ}\). Substitute into the equation \(128^{\circ}+x = 180^{\circ}\).
Subtract \(128^{\circ}\) from both sides: \(x=180^{\circ}- 128^{\circ}\).

$$x = 52^{\circ}$$

Answer:

\(52\)