Question

look at the table you completed. which wave transmits more energy per second?

Explanation:

Step1: Determine amplitude

The amplitude is the maximum displacement from the equilibrium position. By observing the graphs, we can see that the maximum displacement (amplitude) is the same for both waves.

Step2: Determine frequency

The frequency is the number of complete - cycles per unit time. Wave 1 has more cycles in the same horizontal distance (or time interval represented horizontally), so the frequency of Wave 1 is greater.

Step3: Determine energy per second

The energy per second of a wave is proportional to the square of the amplitude and the square of the frequency ($E\propto A^{2}f^{2}$). Since the amplitudes are equal and the frequency of Wave 1 is greater, Wave 1 transmits more energy per second.

Answer:

The amplitude is equal for both waves.
The frequency is greater for Wave 1.
Wave 1 transmits more energy per second.