QUESTION IMAGE
Question
look at this graph:
what is the equation of the line in point - slope form?
use the red point in your equation. write your answer using integers, proper fractions, and improper fractions in simplest form.
$y - \square = \square(x - \square)$
Step1: Identify the red point
From the graph, the red point has coordinates \((3, 10)\) (assuming the grid and the line's position; let's confirm the slope too). Wait, let's check another point. The line passes through \((0, -7)\)? Wait, no, let's find two points. Let's see, when \(x = 1\), \(y =?\) Wait, the red point is at \((3, 10)\)? Wait, maybe better to find slope. Let's take two points: when \(x = 1\), \(y =?\) Wait, the line crosses the y-axis? Wait, no, let's look at the grid. The red point is at \((3, 10)\)? Wait, maybe the red point is \((3, 10)\), and another point: when \(x = 0\), \(y = -7\)? No, wait, let's calculate slope. Let's take two points: let's say \((1, 3)\)? No, maybe the red point is \((3, 10)\) and the line passes through \((1, 2)\)? Wait, no, let's do it properly.
Wait, the point-slope form is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line, and \(m\) is the slope.
First, find the slope. Let's pick two points. Let's see, the line passes through \((1, 2)\)? No, wait, when \(x = 1\), \(y =?\) Wait, the red point is at \((3, 10)\), and let's see another point. Let's take \((0, -7)\)? No, that doesn't seem. Wait, maybe the red point is \((3, 10)\) and the line has a slope. Let's calculate slope between \((3, 10)\) and \((0, -7)\)? No, that slope would be \(\frac{10 - (-7)}{3 - 0} = \frac{17}{3}\), which doesn't make sense. Wait, maybe I misread the red point. Wait, the graph: the red point is at \((3, 10)\)? Wait, the y-axis goes up to 10, and the x-axis to 10. Let's check the line: when \(x = 1\), \(y = 3\)? No, maybe the red point is \((3, 10)\) and the slope is 3? Wait, let's see: if \(x = 3\), \(y = 10\), and when \(x = 0\), \(y = 1\)? No, that's not. Wait, maybe the red point is \((3, 10)\) and the slope is 3. Let's check: \(y - 10 = 3(x - 3)\). Let's expand: \(y = 3x - 9 + 10 = 3x + 1\). Does that fit? If \(x = 1\), \(y = 4\)? No, maybe not. Wait, maybe the red point is \((3, 10)\) and the slope is 3. Wait, maybe I made a mistake. Let's re-examine the graph.
Wait, the line passes through (1, 3) and (3, 9)? No, the red point is at (3, 10). Wait, maybe the slope is 3. Let's check: from (0, 1) to (3, 10): slope is (10 - 1)/(3 - 0) = 9/3 = 3. Yes, that works. So the red point is (3, 10), slope is 3.
Step2: Plug into point-slope form
Point-slope form is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1) = (3, 10)\) and \(m = 3\). So \(y - 10 = 3(x - 3)\).
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\(y - \boxed{10} = \boxed{3}(x - \boxed{3})\)