Question

a local coffee store is curious about the size beverages their customers are ordering. the beverages come in three sizes: small, medium, and large. an employee runs a simulation of 15 random outcomes using the values 1, 2, and 3 to represent small, medium, and large, respectively. what is the simulated probability that a customer will order the small beverage? 2 2 3 1 1 2 2 3 1 1 3 2 1 1 3 (1 point) 0.167 0.400 0.333 0.500

Explanation:

Step1: Count the number of times 1 (small) appears

Count the number of 1s in the sequence \(2\ 2\ 3\ 1\ 1\ 2\ 2\ 3\ 1\ 1\ 3\ 2\ 1\ 1\ 3\). There are \(6\) ones.

Step2: Calculate the probability

The formula for probability is \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the number of favorable outcomes (small, i.e., 1) is \(n = 6\), and the total number of outcomes is \(N=15\). So \(P=\frac{6}{15}\).
Simplify \(\frac{6}{15}=\frac{2}{5}=0.4\)

Answer:

\(0.400\)