Question

lets try it: speed and mass in kinetic energy
if javier rolls a 10 - pound bowling ball and a 1 - pound tennis ball down the same hill, which one will have more kinetic energy and why?

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy is \(K.E.=\frac{1}{2}mv^{2}\), where \(m\) is mass and \(v\) is velocity.

Step2: Analyze the velocity

Since both balls roll down the same hill, they will have the same final velocity \(v\) (assuming no air - resistance and similar rolling conditions).

Step3: Compare the masses

The mass of the bowling ball \(m_{1}=10\) pounds and the mass of the tennis ball \(m_{2} = 1\) pound. Given \(v_{1}=v_{2}=v\), using the kinetic energy formula \(K.E.=\frac{1}{2}mv^{2}\), when we calculate \(K.E._{1}=\frac{1}{2}m_{1}v^{2}\) and \(K.E._{2}=\frac{1}{2}m_{2}v^{2}\), and substitute \(m_{1}>m_{2}\)

Answer:

The 10 - pound bowling ball will have more kinetic energy. Because when two objects have the same velocity (rolling down the same hill), the object with a larger mass (since \(K.E.=\frac{1}{2}mv^{2}\) and \(v\) is the same for both) will have more kinetic energy.