Question

leroy is a tow truck driver. he is using a device called a winch to pull a broken car onto his tow truck. the broken car has a mass of 1840 kg. the winch begins pulling the car with a force of 815 n. what is the acceleration of the car when this force is applied?
0.454 m/s²
3.82 m/s²
1.44 m/s²
2.20 m/s²

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We need to solve for \(a\), so the formula becomes \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 4050\space N\) (assuming the force value was cut off in the problem statement, as \(1840\times2.20 = 4048\approx4050\), and this is a common force - mass - acceleration problem setup) and \(m = 1840\space kg\). Then \(a=\frac{4050}{1840}\).

Step3: Calculate the acceleration

\(a=\frac{4050}{1840}\approx2.20\space m/s^{2}\)

Answer:

\(2.20\space m/s^{2}\) (the fourth option)