Question

1. laylas pet rabbit lives in a rectangular pen with a perimeter of 28 feet. one side of the pen is 8 feet long. how much space does laylas rabbit have to play in (area)?

Explanation:

Step1: Find the other side length

The formula for the perimeter of a rectangle is \(P = 2(l + w)\). Given \(P=28\) feet and one side \(w = 8\) feet.
Substitute into the formula: \(28=2(l + 8)\).
First, divide both sides by 2: \(\frac{28}{2}=l + 8\), so \(14=l + 8\).
Then subtract 8 from both sides: \(l=14 - 8=6\) feet.

Step2: Calculate the area

The formula for the area of a rectangle is \(A=l\times w\).
Substitute \(l = 6\) feet and \(w = 8\) feet: \(A=6\times8 = 48\) square feet.

Answer:

48 square feet