Question

a 0.5 kg drone flies at a speed of 20 m/s. how much kinetic energy does the drone have? remember : $e_k = \frac{1}{2}mv^2$ $e_k = ?$ j

Explanation:

Step1: Identify given values

Mass \( m = 0.5 \, \text{kg} \), speed \( v = 20 \, \text{m/s} \), formula \( E_K=\frac{1}{2}mv^2 \).

Step2: Substitute values into formula

Substitute \( m = 0.5 \) and \( v = 20 \) into \( E_K=\frac{1}{2}mv^2 \):
\( E_K=\frac{1}{2}\times0.5\times(20)^2 \)

Step3: Calculate step by step

First, calculate \( (20)^2 = 400 \).
Then, \( \frac{1}{2}\times0.5 = 0.25 \).
Finally, \( 0.25\times400 = 100 \).

Answer:

100