Question

kbr + cl₂ → kcl + br₂
synthesis
decomposition
single displacement
double displacement
combustion

Explanation:

• Synthesis: Two or more substances combine to form a single product. In the given reaction \(KBr + Cl_2

ightarrow KCl+Br_2\), there are two products (\(KCl\) and \(Br_2\)), so it is not a synthesis reaction.

• Decomposition: A single compound breaks down into two or more simpler substances. Here, there are two reactants (\(KBr\) and \(Cl_2\)), so it is not a decomposition reaction.
• Single Displacement: One element replaces another element in a compound. The general form is \(A + BC

ightarrow AC + B\). In the reaction \(KBr+Cl_2
ightarrow KCl + Br_2\), \(Cl\) (from \(Cl_2\)) replaces \(Br\) (from \(KBr\)). The reaction can be rewritten as \(2KBr+Cl_2 = 2KCl+Br_2\) (balanced equation).

• Double Displacement: Two compounds exchange their ions. The general form is \(AB + CD

ightarrow AD+CB\). Since in our reaction an element (\(Cl_2\)) reacts with a compound (\(KBr\)), it is not a double - displacement reaction.

• Combustion: A substance reacts with oxygen, usually producing heat and light. There is no oxygen involved in the given reaction \(KBr + Cl_2

ightarrow KCl+Br_2\), so it is not a combustion reaction.

Answer:

C. Single Displacement