Question

joans tea was 76°f. after warming it in the microwave the temperature increased 33°f. he let it cool down 10°f before taking a sip. what is the temperature of his tea now?

Explanation:

Step1: Calculate the temperature after warming

The initial temperature is \(76^{\circ}F\). After warming, the temperature increased by \(33^{\circ}F\). So we add these two values: \(76 + 33\).

$$76+33 = 109^{\circ}F$$

Step2: Calculate the final temperature

Then it cooled down by \(10^{\circ}F\). So we subtract \(10\) from the result of Step 1: \(109- 10\).

$$109 - 10=99^{\circ}F$$

Answer:

\(99^{\circ}F\)