QUESTION IMAGE
Question
if ( jk = 60 ), find ( jn ).
Step1: 确定\(N\)为重心
因为\(IL = LJ = 25\),\(IK = KH = 30\),\(JM = MH = 39\),所以\(N\)是\(\triangle IJH\)三条中线的交点,即重心。
Step2: 利用重心性质计算\(JN\)
根据重心性质:重心到顶点的距离与重心到对边中点的距离之比是\(2:1\),即\(JK = 3JN\)。已知\(JK = 60\),则\(JN=\frac{1}{3}JK\)。
将\(JK = 60\)代入\(JN=\frac{1}{3}JK\),可得\(JN=\frac{1}{3}\times60 = 20\)。
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\(20\)