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Question
jen walks straight across a rectangular park to school each morning. the dimensions of the park are shown below. which measurement is closest to the distance jen walks to school each morning? a 86 yards b 120 yards c 3,500 yards d 7,400 yards
Step1: Apply Pythagorean theorem
In a right - triangle (the path Jen walks is the hypotenuse of a right - triangle with legs \(a = 70\) yards and \(b=50\) yards), the Pythagorean theorem is \(c^{2}=a^{2}+b^{2}\), where \(c\) is the length of the hypotenuse.
So, \(c^{2}=70^{2}+50^{2}\).
Step2: Calculate \(a^{2}\) and \(b^{2}\)
\(70^{2}=70\times70 = 4900\) and \(50^{2}=50\times50=2500\). Then \(c^{2}=4900 + 2500\).
Step3: Sum the values
\(c^{2}=7400\).
Step4: Find \(c\)
\(c=\sqrt{7400}\approx86\) (since \(\sqrt{7396}=86\) and \(7400\) is very close to \(7396\)).
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A. 86 yards