Question

a jar has 8 jellybeans: 5 red, 3 green. if 1 jellybean is randomly drawn, replaced, and then 1 is drawn again, what is the probability of getting green both times? event a: green on 1st draw event b: green on 2nd draw p(a, then b) = ?/? give your answer as a fraction in simplest form. compound probability independent events p(a, then b) = p(a) · p(b)

Explanation:

Step1: Calculate P(A)

Total jellybeans = 8, green = 3. So $P(A) = \frac{3}{8}$.

Step2: Calculate P(B)

Since replaced, $P(B) = \frac{3}{8}$.

Step3: Multiply probabilities

$P(A \text{ then } B) = P(A) \times P(B) = \frac{3}{8} \times \frac{3}{8} = \frac{9}{64}$.

Answer:

$\frac{9}{64}$