Question

jamie wants to know the volume of his gold ring in cubic centimeters. he gets a rectangular glass with a base 3 cm by 2 cm and fills the glass 4 cm high with water. jamie drops his gold ring in the glass and measures the new height of the water to be 4.25 cm. what is the volume of jamies ring in cubic centimeters? \boxed{} cm³ two images of rectangular glasses with water, one with height 4 cm, one with height 4.25 cm and a gold ring inside

Explanation:

Step1: Calculate the base area of the glass

The base of the glass is a rectangle with length \(l = 3\space cm\) and width \(w=2\space cm\). The area of a rectangle \(A = l\times w\). So, \(A=3\times2 = 6\space cm^{2}\)

Step2: Calculate the change in water height

The initial height of water \(h_1 = 4\space cm\) and the final height \(h_2=4.25\space cm\). The change in height \(\Delta h=h_2 - h_1\). So, \(\Delta h=4.25 - 4=0.25\space cm\)

Step3: Calculate the volume of the ring

The volume of the ring is equal to the volume of water displaced. The volume of a rectangular - prism (the displaced water) \(V = A\times\Delta h\). Substitute \(A = 6\space cm^{2}\) and \(\Delta h = 0.25\space cm\) into the formula. So, \(V=6\times0.25=1.5\space cm^{3}\)

Answer:

\(1.5\)