Question

g) iron + oxygen → iron oxide
skeleton equation
chemical equation
type of reaction
h) potassium + bromine → potassium bromide
skeleton equation
chemical equation
type of reaction
i) magnesium + hydroxide → magnesium hydroxide
skeleton equation
chemical equation
type of reaction
j) lithium + carbonate → lithium carbonate
skeleton equation
chemical equation
type of reaction

Explanation:

Step1: Write skeleton equations

• For g) iron (\(Fe\)) + oxygen (\(O_2\)) → iron oxide (\(Fe_2O_3\)): Skeleton equation is \(Fe+O_2

ightarrow Fe_2O_3\)

• For h) potassium (\(K\)) + bromine (\(Br_2\)) → potassium bromide (\(KBr\)): Skeleton equation is \(K + Br_2

ightarrow KBr\)

• For i) magnesium (\(Mg\)) + hydroxide (\(OH^-\)) → magnesium hydroxide (\(Mg(OH)_2\)): Skeleton equation is \(Mg+OH^-

ightarrow Mg(OH)_2\) (assuming hydroxide as \(OH^-\) in ionic form for simplicity of skeleton, in a more proper sense if considering compound, but as per naming \(Mg + H_2O
ightarrow Mg(OH)_2\) could also be a way if hydroxide source is water, but following the naming in problem \(Mg+OH^-
ightarrow Mg(OH)_2\))

• For j) lithium (\(Li\)) + carbonate (\(CO_3^{2 -}\)) → lithium carbonate (\(Li_2CO_3\)): Skeleton equation is \(Li+CO_3^{2 -}

ightarrow Li_2CO_3\) (assuming carbonate as \(CO_3^{2 -}\) in ionic form for simplicity of skeleton, if considering compound source like \(CO_2\) and \(H_2O\) etc. but following naming \(Li+CO_3^{2 -}
ightarrow Li_2CO_3\))

Step2: Balance chemical equations

• For g):
• Balance \(Fe\): \(4Fe+O_2

ightarrow 2Fe_2O_3\)

• Then balance \(O\): \(4Fe + 3O_2=2Fe_2O_3\)
• For h):
• Balance \(Br\): \(K+Br_2

ightarrow 2KBr\)

• Then balance \(K\): \(2K + Br_2 = 2KBr\)
• For i):
• Balance \(OH^-\): \(Mg+2OH^-

ightarrow Mg(OH)_2\) (if hydroxide is from a compound like \(2H_2O\) and considering \(Mg + 2H_2O=Mg(OH)_2+H_2\), but if following the simple ion - based balancing as per naming in problem \(Mg + 2OH^-=Mg(OH)_2\))

• For j):
• Balance \(Li\): \(2Li+CO_3^{2 -}

ightarrow Li_2CO_3\) (if carbonate is from a compound like \(CO_2\) and \(H_2O\) and considering \(2Li+CO_2 + H_2O=Li_2CO_3+H_2\), but following the simple ion - based balancing as per naming \(2Li+CO_3^{2 -}=Li_2CO_3\))

Step3: Determine reaction type

• For g): Combination reaction (two substances combine to form one product \(4Fe + 3O_2=2Fe_2O_3\))
• For h): Combination reaction (\(2K + Br_2 = 2KBr\))
• For i): Combination reaction (if we consider the ion - based equation \(Mg + 2OH^-=Mg(OH)_2\) or \(Mg + 2H_2O=Mg(OH)_2+H_2\) (latter is a single - displacement in a more complex view, but if following the simple naming in problem as combination of \(Mg\) and \(OH^-\) to form \(Mg(OH)_2\))
• For j): Combination reaction (if we consider the ion - based equation \(2Li+CO_3^{2 -}=Li_2CO_3\) or if from compounds \(2Li+CO_2 + H_2O=Li_2CO_3+H_2\) (latter is more complex, but following the simple naming as combination of \(Li\) and \(CO_3^{2 -}\) to form \(Li_2CO_3\))

Answer:

• g)
• Skeleton equation: \(Fe+O_2

ightarrow Fe_2O_3\)

• Chemical equation: \(4Fe + 3O_2=2Fe_2O_3\)
• Type of reaction: Combination reaction
• h)
• Skeleton equation: \(K + Br_2

ightarrow KBr\)

• Chemical equation: \(2K + Br_2 = 2KBr\)
• Type of reaction: Combination reaction
• i)
• Skeleton equation: \(Mg+OH^-

ightarrow Mg(OH)_2\)

• Chemical equation: \(Mg + 2OH^-=Mg(OH)_2\) (or \(Mg + 2H_2O=Mg(OH)_2+H_2\) depending on hydroxide source view)
• Type of reaction: Combination reaction (or single - displacement if \(Mg + 2H_2O=Mg(OH)_2+H_2\))
• j)
• Skeleton equation: \(Li+CO_3^{2 -}

ightarrow Li_2CO_3\)

• Chemical equation: \(2Li+CO_3^{2 -}=Li_2CO_3\) (or \(2Li+CO_2 + H_2O=Li_2CO_3+H_2\) depending on carbonate source view)
• Type of reaction: Combination reaction (or more complex if considering compound sources)