Question

for the inverse variation equation $p = \frac{8}{v}$, what is the value of $v$ when $p = \frac{1}{2}$?\
$\frac{1}{16}$ $\frac{1}{4}$ 4\
16

Explanation:

Step1: Substitute \( p = \frac{1}{2} \) into the equation

We have the inverse variation equation \( p=\frac{8}{V} \). Substitute \( p = \frac{1}{2} \) into it, so we get \( \frac{1}{2}=\frac{8}{V} \).

Step2: Solve for \( V \)

Cross - multiply the equation \( \frac{1}{2}=\frac{8}{V} \). According to the cross - multiplication rule \( \frac{a}{b}=\frac{c}{d}\Rightarrow ad = bc \), here \( a = 1 \), \( b = 2 \), \( c = 8 \), \( d = V \), so \( 1\times V=2\times8 \), which simplifies to \( V = 16 \).

Answer:

16