Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

the inverse of a matrix in exercises 5, 6, 7, 8, 9, 10, 11, and 12, sho…

Question

the inverse of a matrix in exercises 5, 6, 7, 8, 9, 10, 11, and 12, show that ( b ) is the inverse

  1. ( a = \begin{bmatrix} 2 & 1 \\ 5 & 3 end{bmatrix}, quad b = \begin{bmatrix} 3 & -1 \\ -5 & 2 end{bmatrix} )
  1. ( a = \begin{bmatrix} 1 & -1 \\ -1 & 2 end{bmatrix}, quad b = \begin{bmatrix} 2 & 1 \\ 1 & 1 end{bmatrix} )

Explanation:

Problem 5

To show that \( B \) is the inverse of \( A \), we need to verify that \( AB = I \) and \( BA = I \), where \( I \) is the identity matrix.

Step 1: Calculate \( AB \)

Given \( A =

$$\begin{bmatrix} 2 & 1 \\ 5 & 3 \end{bmatrix}$$

\) and \( B =

$$\begin{bmatrix} 3 & -1 \\ -5 & 2 \end{bmatrix}$$

\)

$$ LATEXBLOCK2 $$
Step 2: Calculate \( BA \)
$$ LATEXBLOCK3 $$

Since \( AB = I \) and \( BA = I \), \( B \) is the inverse of \( A \).

Problem 6

To show that \( B \) is the inverse of \( A \), we need to verify that \( AB = I \) and \( BA = I \), where \( I \) is the identity matrix.

Step 1: Calculate \( AB \)

Given \( A =

$$\begin{bmatrix} 1 & -1 \\ -1 & 2 \end{bmatrix}$$

\) and \( B =

$$\begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}$$

\)

$$ LATEXBLOCK6 $$
Step 2: Calculate \( BA \)
$$ LATEXBLOCK7 $$

Since \( AB = I \) and \( BA = I \), \( B \) is the inverse of \( A \).

Answer:

Problem 5

To show that \( B \) is the inverse of \( A \), we need to verify that \( AB = I \) and \( BA = I \), where \( I \) is the identity matrix.

Step 1: Calculate \( AB \)

Given \( A =

$$\begin{bmatrix} 2 & 1 \\ 5 & 3 \end{bmatrix}$$

\) and \( B =

$$\begin{bmatrix} 3 & -1 \\ -5 & 2 \end{bmatrix}$$

\)

$$ LATEXBLOCK2 $$
Step 2: Calculate \( BA \)
$$ LATEXBLOCK3 $$

Since \( AB = I \) and \( BA = I \), \( B \) is the inverse of \( A \).

Problem 6

To show that \( B \) is the inverse of \( A \), we need to verify that \( AB = I \) and \( BA = I \), where \( I \) is the identity matrix.

Step 1: Calculate \( AB \)

Given \( A =

$$\begin{bmatrix} 1 & -1 \\ -1 & 2 \end{bmatrix}$$

\) and \( B =

$$\begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}$$

\)

$$ LATEXBLOCK6 $$
Step 2: Calculate \( BA \)
$$ LATEXBLOCK7 $$

Since \( AB = I \) and \( BA = I \), \( B \) is the inverse of \( A \).