Question

instructions solve the following problem and choose the best answer. question the floor of a rectangular room is to be covered with square floor tiles with 1 - foot sides. the floor of the room is 18 feet long and 12 feet wide. if the square tiles cost $4 each, how much would it cost to completely cover the floor with these tiles? $120 $216 $240 $864

Explanation:

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Step1: Calculate the area of \(1\) tile

The area of a square tile \(A_{\text{tile}}\) with side \(s = 1\) foot is \(A_{\text{tile}}=s\times s\).
Since \(s = 1\) foot, \(A_{\text{tile}}=1\times1=1\) square - foot.

Step2: Calculate the area of the rectangular room

The area of a rectangle \(A_{\text{room}}\) with length \(l = 18\) feet and width \(w = 12\) feet is \(A_{\text{room}}=l\times w\).
Substitute \(l = 18\) and \(w = 12\) into the formula: \(A_{\text{room}}=18\times12 = 216\) square - feet.

Step3: Determine the number of tiles

The number of tiles \(n=\frac{A_{\text{room}}}{A_{\text{tile}}}\).
Since \(A_{\text{room}} = 216\) square - feet and \(A_{\text{tile}}=1\) square - foot, \(n = 216\) tiles.

Step4: Calculate the total cost

The cost of each tile is \(C_{\text{per - tile}}=\$4\).
The total cost \(C=n\times C_{\text{per - tile}}\).
Substitute \(n = 216\) and \(C_{\text{per - tile}} = 4\) into the formula: \(C=216\times4=\$864\).

Answer:

\(\$864\)