Question

indicator measurement: you mastered a dial indicator to a gage block that measures 2.5\ in length. you are now inspecting parts and your first part measures 0.05\ on the dial indicator. what is the actual length of the part? 2.5\ 2.45\ 2.55\ 2.25\

Explanation:

Step1: Understand the principle

The actual length of the part is the length of the gage block plus the reading on the dial indicator.

Step2: Calculate the actual length

The length of the gage block is \(2.5^{\prime\prime}\) and the dial indicator reads \(0.05^{\prime\prime}\). So the actual length \(L = 2.5+ 0.05\).

$$L=2.5 + 0.05=2.55^{\prime\prime}$$

Answer:

C. \(2.55^{\prime\prime}\)