Question

identifying types of reactions by matter
balance each of the following reactions and identify each type of reaction by matter.

1. \text{nabr} + \text{ca(oh)}_2 \

ightarrow \text{cabr}_2 + \text{naoh}

1. \text{nh}_3 + \text{h}_2(\text{so}_4) \

ightarrow (\text{nh}_4)_2(\text{so}_4)

Explanation:

Step1: Analyze Reaction 1

The reaction is between NaBr and Ca(OH)₂. Let's write the unbalanced equation: $NaBr + Ca(OH)_2
ightarrow CaBr_2 + NaOH$. To balance, we look at Br: left has 1, right has 2. So put 2 in front of NaBr: $2NaBr + Ca(OH)_2
ightarrow CaBr_2 + NaOH$. Now Na: left 2, right 1. Put 2 in front of NaOH: $2NaBr + Ca(OH)_2 = CaBr_2 + 2NaOH$. This is a double - displacement reaction (ions swap: $Na^+$ with $Ca^{2+}$ and $Br^-$ with $OH^-$).

Step2: Analyze Reaction 2

The reaction is between NH₃ and H₂SO₄. The unbalanced equation: $NH_3 + H_2SO_4
ightarrow (NH_4)_2SO_4$. Let's balance N: left 1, right 2. Put 2 in front of NH₃: $2NH_3 + H_2SO_4 = (NH_4)_2SO_4$. This is an acid - base (neutralization) reaction, also a type of combination reaction (or double - displacement in terms of ion interaction, but more specifically acid - base).

Answer:

1. Balanced equation: $\boldsymbol{2NaBr + Ca(OH)_2 = CaBr_2 + 2NaOH}$, Reaction Type: Double - Displacement
2. Balanced equation: $\boldsymbol{2NH_3 + H_2SO_4=(NH_4)_2SO_4}$, Reaction Type: Acid - Base (Neutralization)