Question

identify the strong base in the following reaction and predict the products:
hclo₄(aq) + naoh(aq) —→ ?
○ there is no strong base in this reaction; the products are impossible to predict
○ naoh; nah(aq) + hclo₄(l)
○ hclo₄; naclo₄(aq) + h₂o(l)
○ naoh; naclo₄(aq) + h₂o(l)

Explanation:

Step1: Identify Reaction Type

This is an acid - base neutralization reaction. \(HClO_4(aq)\) is a strong acid (perchloric acid), and \(NaOH(aq)\) is a strong base (sodium hydroxide). In a neutralization reaction between a strong acid and a strong base, the products are a salt and water.

Step2: Determine Products

The general formula for the neutralization of an acid \(HA\) and a base \(MOH\) is \(HA+MOH
ightarrow MA + H_2O\). Here, \(H^+\) from \(HClO_4\) combines with \(OH^-\) from \(NaOH\) to form \(H_2O\), and \(Na^+\) from \(NaOH\) combines with \(ClO_4^-\) from \(HClO_4\) to form the salt \(NaClO_4\). So the reaction is \(HClO_4(aq)+NaOH(aq)
ightarrow NaClO_4(aq)+H_2O(l)\), and the strong base here is \(NaOH\).

Answer:

The correct option is: \(NaOH\); \(NaClO_4(aq)+H_2O(l)\) (the last option among the given choices which is "NaOH: NaClO₄(aq) + H₂O(l)")