Question

1. identify the reaction type, the reactants, and the products.

reaction
aqueous solutions of potassium hydroxide and cobalt(iii) nitrate are mixed.
reaction type
reactant(s)
product(s)
choices:
cono₃
co(no₃)₃
co₃n
co₃no
koh
con
co₃oh
co(oh)₃
kno₃
cooh
k(no₃)₃
co₃k
oh(no₃)₃
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Explanation:

Step1: Identify Reactants

The reactants are potassium hydroxide (KOH) and cobalt(III) nitrate ($\ce{Co(NO_{3})_{3}}$) since the reaction is between their aqueous solutions.

Step2: Determine Reaction Type

This is a double - displacement (precipitation) reaction. In double - displacement reactions, the cations and anions of two compounds exchange places. The general form is $\ce{AB + CD -> AD + CB}$.

Step3: Predict Products

For the reaction between $\ce{KOH}$ and $\ce{Co(NO_{3})_{3}}$, the potassium ion ($\ce{K+}$) will combine with the nitrate ion ($\ce{NO_{3}^-}$) to form potassium nitrate ($\ce{KNO_{3}}$), and the cobalt(III) ion ($\ce{Co^{3+}}$) will combine with the hydroxide ion ($\ce{OH^-}$) to form cobalt(III) hydroxide ($\ce{Co(OH)_{3}}$). The chemical equation for the reaction is $\ce{3KOH(aq) + Co(NO_{3})_{3}(aq) -> 3KNO_{3}(aq) + Co(OH)_{3}(s)}$.

Answer:

• Reaction Type: Double - Displacement (Precipitation)
• Reactant(s): $\ce{KOH}$ + $\ce{Co(NO_{3})_{3}}$
• Product(s): $\ce{KNO_{3}}$ + $\ce{Co(OH)_{3}}$