Question

identify the oxidizing agent and the reducing agent for
zn(s) + cu²⁺(aq) → zn²⁺(aq) + cu(s)
express your answers as chemical formulas separated by a comma.
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oxidizing agent, reducing agent

Explanation:

Step1: Analyze oxidation states

• For \(Zn\) in \(Zn(s)\), oxidation state is \(0\). In \(Zn^{2 +}(aq)\), it is \(+ 2\). So \(Zn\) is oxidized (\(Zn

ightarrow Zn^{2+}+2e^{-}\)).

• For \(Cu^{2 +}\) in \(Cu^{2 +}(aq)\), oxidation state is \(+ 2\). In \(Cu(s)\), it is \(0\). So \(Cu^{2+}\) is reduced (\(Cu^{2+}+2e^{-}

ightarrow Cu\)).

Step2: Determine oxidizing and reducing agents

• The substance that is reduced is the oxidizing agent. So \(Cu^{2+}\) is the oxidizing agent.
• The substance that is oxidized is the reducing agent. So \(Zn\) is the reducing agent.

Answer:

\(Cu^{2+},Zn\)