Question

in $sp^{2}$-hybridized orbitals, how many $p$-orbitals remain to form multiple bonds?

Explanation:

Step1: Recall the number of p - orbitals in an atom

In an atom, there are 3 \(p\) - orbitals (\(p_x\), \(p_y\), \(p_z\)).

Step2: Calculate the number of \(p\) - orbitals used in \(sp^{2}\) hybridization

In \(sp^{2}\) hybridization, 2 \(p\) - orbitals are used for hybridization (along with 1 \(s\) - orbital).

Step3: Determine the remaining \(p\) - orbitals

The number of remaining \(p\) - orbitals is \(3 - 2=1\).

Answer:

1