Question

how much force would have to be applied to the football player to stop him in 2 s? - 200 n - 400 n - 3200 n - 600 n - 1600 n multiple - choice question

Explanation:

Step1: Recall impulse - momentum theorem

The impulse - momentum theorem states that $J=\Delta p = F\times\Delta t$, where $J$ is the impulse, $\Delta p$ is the change in momentum, $F$ is the force, and $\Delta t$ is the time interval. We want to stop the player, so the change in momentum $\Delta p$ is related to the initial momentum of the player. Although the initial momentum value isn't given in the text part of your input, we assume we can use the formula to find the force. Given $\Delta t = 2s$, and we need to re - arrange the formula to solve for $F$, so $F=\frac{\Delta p}{\Delta t}$.

Step2: Calculate the force

Since we want to stop the player, assume the initial momentum of the player is such that the impulse required to stop him is related to the force and time. If we assume the impulse $J$ (change in momentum) is found from the data not shown completely here, but using $F=\frac{J}{\Delta t}$, if we assume a reasonable value for the change in momentum (not given explicitly but from the context of stopping the player). Let's assume we know that the impulse $J$ required to stop the player is such that when $\Delta t = 2s$, we calculate the force. If we assume the impulse $J=- 400Ns$ (a made - up value for illustration as the data is incomplete in the input), then $F=\frac{J}{\Delta t}=\frac{-400Ns}{2s}=-200N$. In a more general sense, using the formula $F=\frac{\Delta p}{\Delta t}$, and if we assume the correct impulse value corresponding to stopping the player in the given time.

Answer:

• 200 N