Question

how many valence electrons does oxygen have atoms have? 1s²2s²2p⁴ 2 6 8 4

Explanation:

Step1: Identify valence shell

Valence electrons are in the outermost shell. For oxygen, the electron configuration is \(1s^{2}2s^{2}2p^{4}\). The outermost shell is the second shell (\(n = 2\)), which has \(2s^{2}2p^{4}\).

Step2: Calculate valence electrons

Add the electrons in the outermost - shell. The number of electrons in \(2s\) is \(2\) and in \(2p\) is \(4\). So, \(2 + 4=6\).

Answer:

6