Question

how many total atoms of each element are present in the following formulas?
4 alcl₃ + 3 al₂(so₃)₃ + 3 al₂o₃
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aluminum (al)
chlorine (cl)
sulfur (s)
oxygen (o)
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Explanation:

Step1: Calculate the number of Al atoms

• In \(4AlCl_3\): \(4\times1 = 4\) Al atoms.
• In \(3Al_2(SO_3)_3\): \(3\times2=6\) Al atoms.
• In \(3Al_2O_3\): \(3\times2 = 6\) Al atoms.
• Total Al atoms: \(4 + 6+6=16\).

Step2: Calculate the number of Cl atoms

• In \(4AlCl_3\): \(4\times3 = 12\) Cl atoms.
• Other compounds (\(3Al_2(SO_3)_3\) and \(3Al_2O_3\)) have no Cl atoms.
• Total Cl atoms: \(12\).

Step3: Calculate the number of S atoms

• In \(3Al_2(SO_3)_3\): \(3\times3 = 9\) S atoms.
• Other compounds (\(4AlCl_3\) and \(3Al_2O_3\)) have no S atoms.
• Total S atoms: \(9\).

Step4: Calculate the number of O atoms

• In \(3Al_2(SO_3)_3\): \(3\times(3\times3)=27\) O atoms.
• In \(3Al_2O_3\): \(3\times3 = 9\) O atoms.
• Other compound (\(4AlCl_3\)) has no O atoms.
• Total O atoms: \(27+9 = 36\).

Answer:

Aluminum (\(Al\)): \(16\)
Chlorine (\(Cl\)): \(12\)
Sulfur (\(S\)): \(9\)
Oxygen (\(O\)): \(36\)