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Question
how many moles of pbcl₂ are produced when 16 moles alcl₃ are consumed?
3pb(no₃)₂ + 2alcl₃ → 3pbcl₂ + 2al(no₃)₃
mol pbcl₂
Step1: Analyze the mole ratio
From the balanced chemical equation \(3Pb(NO_3)_2 + 2AlCl_3
ightarrow3PbCl_2 + 2Al(NO_3)_3\), the mole ratio of \(AlCl_3\) to \(PbCl_2\) is \(2:3\).
Step2: Set up the proportion
Let \(x\) be the moles of \(PbCl_2\) produced. Using the mole - ratio, we have \(\frac{2}{3}=\frac{16}{x}\).
Cross - multiply: \(2x = 3\times16\).
Step3: Solve for \(x\)
\(2x=48\), then \(x=\frac{48}{2}\).
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