Question

how many moles of o₂ are needed to completely react with 54.0 g of al? 4al + 3o₂ → 2al₂o₃ lets set up the conversions first. what goes in the green box? 54.0 g al | 1 mol al | / 26.98 g al | ? 54.0 g al 1 mol al 4 mol al 3 mol o₂

Explanation:

Step1: Analyze the stoichiometry of the reaction

From the balanced chemical equation \(4\text{Al}+3\text{O}_2
ightarrow 2\text{Al}_2\text{O}_3\), we can see that the mole ratio of \(\text{Al}\) to \(\text{O}_2\) is \(4:3\).

Step2: Determine the conversion factor

We need to convert moles of \(\text{Al}\) to moles of \(\text{O}_2\). The conversion factor should be based on the mole ratio from the balanced equation. So the conversion factor is \(\frac{3\text{ mol O}_2}{4\text{ mol Al}}\)

Answer:

\(\frac{3\text{ mol O}_2}{4\text{ mol Al}}\)