Question

how many moles of cu are present in 1.51 x 10^{22} atoms cu? 2.51 x 10^{44} moles cu 9.09 moles cu 9.09 x 10^{45} moles cu 0.0251 moles cu

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \( N_A=6.022\times 10^{23}\text{ atoms/mol}\)

Step2: Use the formula \(n = \frac{N}{N_A}\)

Here \(N = 1.51\times 10^{22}\text{ atoms}\) and \(N_A=6.022\times 10^{23}\text{ atoms/mol}\)

$$n=\frac{1.51\times 10^{22}}{6.022\times 10^{23}}$$

$$n=\frac{1.51}{6.022}\times10^{22 - 23}$$

$$n\approx0.251\times10^{- 1}$$

$$n = 0.0251\text{ mol}$$

Answer:

0.0251 moles Cu