Question

how many grams of water will be required to completely react with 1.00 mol of cao according to the following reaction? cao + h₂o → ca(oh)₂ 0.0555 g 1.00 g 18.0 g 5.55 g

Explanation:

Step1: Determine mole - ratio

From the balanced chemical equation $CaO + H_2O
ightarrow Ca(OH)_2$, the mole - ratio of $CaO$ to $H_2O$ is 1:1. So, 1.00 mol of $CaO$ will react with 1.00 mol of $H_2O$.

Step2: Calculate mass of water

The molar mass of $H_2O$ is $M=(2\times1.008 + 16.00)\text{ g/mol}=18.016\text{ g/mol}\approx18.0\text{ g/mol}$. Using the formula $m = n\times M$, where $n = 1.00\text{ mol}$ and $M = 18.0\text{ g/mol}$, we get $m=1.00\text{ mol}\times18.0\text{ g/mol}=18.0\text{ g}$.

Answer:

18.0 g